What is the greatest number of 3 digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?
  • 1903
  • 2939
  • 3975
  • 4996
Answer:- 1
Explanation:-

Solution:
Greatest number of three digits is 999. LCM of 6, 9 and 12 is 36
On dividing 999 by 36, the remainder obtained is 27.
So, required number = (999 - 27) + 3 = 975

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