What is the greatest number of 3 digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?

Explanation:-

Greatest number of three digits is 999. LCM of 6, 9 and 12 is 36
On dividing 999 by 36, the remainder obtained is 27.
So, required number = (999 - 27) + 3 = 975