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The value of √32 - √128 + √50 correct to 3 places of decimal is √32 - √128 + √50 = ?

11.732
21.141
31.414
41.441

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to question \\ \sqrt{32} - \sqrt{128} + \sqrt{50} \\ \Rightarrow \sqrt{16 \times 2} - \sqrt{64 \times 2} + \sqrt{25 \times 2} \\ \Rightarrow 4 \sqrt{2} - 8 \sqrt{2} + 5 \sqrt{2} \\ \Rightarrow \sqrt{2} \\ \Rightarrow 1.414 \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \sqrt {32} {\text{ }} - \sqrt {128} {\text{ + }}\sqrt {50} \cr & \Rightarrow \sqrt {16 \times 2} - \sqrt {64 \times 2} + \sqrt {25 \times 2} \cr & \Rightarrow 4\sqrt 2 - 8\sqrt 2 + 5\sqrt 2 \cr & \Rightarrow \sqrt 2 \cr & \Rightarrow 1.414 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to question \\ \sqrt{32} - \sqrt{128} + \sqrt{50} \\ \Rightarrow \sqrt{16 \times 2} - \sqrt{64 \times 2} + \sqrt{25 \times 2} \\ \Rightarrow 4 \sqrt{2} - 8 \sqrt{2} + 5 \sqrt{2} \\ \Rightarrow \sqrt{2} \\ \Rightarrow 1.414 \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \sqrt {32} {\text{ }} - \sqrt {128} {\text{ + }}\sqrt {50} \cr & \Rightarrow \sqrt {16 \times 2} - \sqrt {64 \times 2} + \sqrt {25 \times 2} \cr & \Rightarrow 4\sqrt 2 - 8\sqrt 2 + 5\sqrt 2 \cr & \Rightarrow \sqrt 2 \cr & \Rightarrow 1.414 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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