(7.5)3+1(7.5)2−6.5(7.5)3+1(7.5)2−6.5\frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}} is equal to = ?" /> (7.5)3+1(7.5)2−6.5(7.5)3+1(7.5)2−6.5\frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}} is equal to = ?" /> (7.5)3+1(7.5)2−6.5(7.5)3+1(7.5)2−6.5\frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}} is equal to = ?" />

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$\frac{{(7.5)}^{3} + 1}{{(7.5)}^{2} - 6.5}$ $\frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}$ is equal to = ?

12.75
2 $\frac{9}{5}$ $\frac{9}{5}$
34.75
48.5

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to question \\ \Rightarrow \frac{{(7.5)}^{3} + 1}{{(7.5)}^{2} - 6.5} \\ [∴ a^{3} + b^{3} = (a + b) (a^{2} + b^{2} - a b)] \\ \Rightarrow \frac{(7.5 + 1) [{(7.5)}^{2} + 1 - 7.5 \times 1]}{{(7.5)}^{2} - 7.5 \times 1 + 1^{2}} \\ \Rightarrow 8.5 \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \Rightarrow \frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}\,\,\,\,\,\,\, \cr & \,\,\,\,\,\,\,\,\,\,\,\left[ {\therefore {a^3} + {b^3} = \left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)} \right] \cr & \Rightarrow \frac{{\left( {7.5 + 1} \right)\left[ {{{\left( {7.5} \right)}^2} + 1 - 7.5 \times 1} \right]}}{{{{\left( {7.5} \right)}^2} - 7.5 \times 1 + {1^2}}} \cr & \Rightarrow 8.5 \cr}$

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is equal to = ?", "text": "

\frac{{(7.5)}^{3} + 1}{{(7.5)}^{2} - 6.5}

$\frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}$ is equal to = ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to question \\ \Rightarrow \frac{{(7.5)}^{3} + 1}{{(7.5)}^{2} - 6.5} \\ [∴ a^{3} + b^{3} = (a + b) (a^{2} + b^{2} - a b)] \\ \Rightarrow \frac{(7.5 + 1) [{(7.5)}^{2} + 1 - 7.5 \times 1]}{{(7.5)}^{2} - 7.5 \times 1 + 1^{2}} \\ \Rightarrow 8.5 \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \Rightarrow \frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}\,\,\,\,\,\,\, \cr & \,\,\,\,\,\,\,\,\,\,\,\left[ {\therefore {a^3} + {b^3} = \left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)} \right] \cr & \Rightarrow \frac{{\left( {7.5 + 1} \right)\left[ {{{\left( {7.5} \right)}^2} + 1 - 7.5 \times 1} \right]}}{{{{\left( {7.5} \right)}^2} - 7.5 \times 1 + {1^2}}} \cr & \Rightarrow 8.5 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to question \\ \Rightarrow \frac{{(7.5)}^{3} + 1}{{(7.5)}^{2} - 6.5} \\ [∴ a^{3} + b^{3} = (a + b) (a^{2} + b^{2} - a b)] \\ \Rightarrow \frac{(7.5 + 1) [{(7.5)}^{2} + 1 - 7.5 \times 1]}{{(7.5)}^{2} - 7.5 \times 1 + 1^{2}} \\ \Rightarrow 8.5 \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \Rightarrow \frac{{{{\left( {7.5} \right)}^3} + 1}}{{{{\left( {7.5} \right)}^2} - 6.5}}\,\,\,\,\,\,\, \cr & \,\,\,\,\,\,\,\,\,\,\,\left[ {\therefore {a^3} + {b^3} = \left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)} \right] \cr & \Rightarrow \frac{{\left( {7.5 + 1} \right)\left[ {{{\left( {7.5} \right)}^2} + 1 - 7.5 \times 1} \right]}}{{{{\left( {7.5} \right)}^2} - 7.5 \times 1 + {1^2}}} \cr & \Rightarrow 8.5 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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