11.2.3+12.3.4+13.4.5+14.5.611.2.3+12.3.4+13.4.5+14.5.6\frac{1}{{1.2.3}} + \frac{1}{{2.3.4}} + \frac{1}{{3.4.5}} + \frac{1}{{4.5.6}} is equal to = ?" /> 11.2.3+12.3.4+13.4.5+14.5.611.2.3+12.3.4+13.4.5+14.5.6\frac{1}{{1.2.3}} + \frac{1}{{2.3.4}} + \frac{1}{{3.4.5}} + \frac{1}{{4.5.6}} is equal to = ?" /> 11.2.3+12.3.4+13.4.5+14.5.611.2.3+12.3.4+13.4.5+14.5.6\frac{1}{{1.2.3}} + \frac{1}{{2.3.4}} + \frac{1}{{3.4.5}} + \frac{1}{{4.5.6}} is equal to = ?" />

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$\frac{1}{1.2.3} + \frac{1}{2.3.4} + \frac{1}{3.4.5} + \frac{1}{4.5.6}$ $\frac{1}{{1.2.3}} + \frac{1}{{2.3.4}} + \frac{1}{{3.4.5}} + \frac{1}{{4.5.6}}$ is equal to = ?

1 $\frac{7}{30}$ $\frac{7}{{30}}$
2 $\frac{11}{30}$ $\frac{{11}}{{30}}$
3 $\frac{13}{30}$ $\frac{{13}}{{30}}$
4 $\frac{17}{30}$ $\frac{{17}}{{30}}$

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Given expression, \\ \frac{4.5.6 + 5.6 + 2.6 + 2.3}{1.2.3.4.5.6} \\ = \frac{120 + 30 + 12 + 6}{720} \\ = \frac{168}{720} \\ = \frac{7}{30} \end{aligned}

$\eqalign{ & {\text{Given expression,}} \cr & \frac{{4.5.6 + 5.6 + 2.6 + 2.3}}{{1.2.3.4.5.6}} \cr & = \frac{{120 + 30 + 12 + 6}}{{720}} \cr & = \frac{{168}}{{720}} \cr & = \frac{7}{{30}} \cr}$

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is equal to = ?", "text": "

\frac{1}{1.2.3} + \frac{1}{2.3.4} + \frac{1}{3.4.5} + \frac{1}{4.5.6}

$\frac{1}{{1.2.3}} + \frac{1}{{2.3.4}} + \frac{1}{{3.4.5}} + \frac{1}{{4.5.6}}$ is equal to = ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Given expression, \\ \frac{4.5.6 + 5.6 + 2.6 + 2.3}{1.2.3.4.5.6} \\ = \frac{120 + 30 + 12 + 6}{720} \\ = \frac{168}{720} \\ = \frac{7}{30} \end{aligned}

$\eqalign{ & {\text{Given expression,}} \cr & \frac{{4.5.6 + 5.6 + 2.6 + 2.3}}{{1.2.3.4.5.6}} \cr & = \frac{{120 + 30 + 12 + 6}}{{720}} \cr & = \frac{{168}}{{720}} \cr & = \frac{7}{{30}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: