If 3a+4b3a+4b = 3a−4b3c−4d thenIf 3a+4b3a+4b = 3a−4b3c−4d then{\text{If }}\frac{{3a + 4b}}{{3a + 4b}}{\text{ = }}\frac{{3a - 4b}}{{3c - 4d}}{\text{ then}}" /> If 3a+4b3a+4b = 3a−4b3c−4d thenIf 3a+4b3a+4b = 3a−4b3c−4d then{\text{If }}\frac{{3a + 4b}}{{3a + 4b}}{\text{ = }}\frac{{3a - 4b}}{{3c - 4d}}{\text{ then}}" /> If 3a+4b3a+4b = 3a−4b3c−4d thenIf 3a+4b3a+4b = 3a−4b3c−4d then{\text{If }}\frac{{3a + 4b}}{{3a + 4b}}{\text{ = }}\frac{{3a - 4b}}{{3c - 4d}}{\text{ then}}" />

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$If \frac{3 a + 4 b}{3 a + 4 b} = \frac{3 a - 4 b}{3 c - 4 d} then$ ${\text{If }}\frac{{3a + 4b}}{{3a + 4b}}{\text{ = }}\frac{{3a - 4b}}{{3c - 4d}}{\text{ then}}$

1ab = cd
2ad = bc
3ac = bd
4a = b =c ≠ d

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to question \\ \frac{3 a + 4 b}{3 a + 4 b} = \frac{3 a - 4 b}{3 c - 4 d} \\ \Rightarrow \frac{3 a}{4 b} = \frac{3 c}{4 d} \\ \Rightarrow a d = b c \end{aligned}

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", "text": "

If \frac{3 a + 4 b}{3 a + 4 b} = \frac{3 a - 4 b}{3 c - 4 d} then

${\text{If }}\frac{{3a + 4b}}{{3a + 4b}}{\text{ = }}\frac{{3a - 4b}}{{3c - 4d}}{\text{ then}}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to question \\ \frac{3 a + 4 b}{3 a + 4 b} = \frac{3 a - 4 b}{3 c - 4 d} \\ \Rightarrow \frac{3 a}{4 b} = \frac{3 c}{4 d} \\ \Rightarrow a d = b c \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \frac{{3a + 4b}}{{3a + 4b}}{\text{ = }}\frac{{3a - 4b}}{{3c - 4d}} \cr & \Rightarrow \frac{{3a}}{{4b}} = \frac{{3c}}{{4d}} \cr & \Rightarrow ad = bc \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: