3+3364−−−−−−√÷9+17−−−−−√×2319−−−√=?3+3364÷9+17×2319=?\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} = ?" /> 3+3364−−−−−−√÷9+17−−−−−√×2319−−−√=?3+3364÷9+17×2319=?\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} = ?" /> 3+3364−−−−−−√÷9+17−−−−−√×2319−−−√=?3+3364÷9+17×2319=?\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} = ?" />

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Simplify : $\sqrt{3 + \frac{33}{64}} \div \sqrt{9 + \frac{1}{7}} \times 2 \sqrt{3 \frac{1}{9}} = ?$ $\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} = ?$

1 $\frac{45}{256}$ $\frac{{45}}{{256}}$
2 $1 \frac{17}{28}$ $1\frac{{17}}{{28}}$
3 $4 \frac{3}{8}$ $4\frac{3}{8}$
4 $2 \frac{3}{16}$ $2\frac{3}{{16}}$

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to question \\ \sqrt{3 + \frac{33}{64}} \div \sqrt{9 + \frac{1}{7}} \times 2 \sqrt{3 \frac{1}{9}} \\ = \sqrt{\frac{225}{64}} \div \sqrt{\frac{64}{7}} \times 2 \sqrt{\frac{28}{9}} \\ = \sqrt{\frac{225}{64} \times \frac{7}{64} \times \frac{28}{9}} \times 2 \\ = \frac{5 \times 7}{8 \times 4} \times 2 \\ = \frac{35}{16} \\ = 2 \frac{3}{16} \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} \cr & = \sqrt {\frac{{225}}{{64}}} \div \sqrt {\frac{{64}}{7}} \times 2\sqrt {\frac{{28}}{9}} \cr & = \sqrt {\frac{{225}}{{64}} \times \frac{7}{{64}} \times \frac{{28}}{9}} \times 2 \cr & = \frac{{5 \times 7}}{{8 \times 4}} \times 2 \cr & = \frac{{35}}{{16}} \cr & = 2\frac{3}{{16}} \cr}$

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", "text": "Simplify :

\sqrt{3 + \frac{33}{64}} \div \sqrt{9 + \frac{1}{7}} \times 2 \sqrt{3 \frac{1}{9}} = ?

$\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} = ?$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to question \\ \sqrt{3 + \frac{33}{64}} \div \sqrt{9 + \frac{1}{7}} \times 2 \sqrt{3 \frac{1}{9}} \\ = \sqrt{\frac{225}{64}} \div \sqrt{\frac{64}{7}} \times 2 \sqrt{\frac{28}{9}} \\ = \sqrt{\frac{225}{64} \times \frac{7}{64} \times \frac{28}{9}} \times 2 \\ = \frac{5 \times 7}{8 \times 4} \times 2 \\ = \frac{35}{16} \\ = 2 \frac{3}{16} \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} \cr & = \sqrt {\frac{{225}}{{64}}} \div \sqrt {\frac{{64}}{7}} \times 2\sqrt {\frac{{28}}{9}} \cr & = \sqrt {\frac{{225}}{{64}} \times \frac{7}{{64}} \times \frac{{28}}{9}} \times 2 \cr & = \frac{{5 \times 7}}{{8 \times 4}} \times 2 \cr & = \frac{{35}}{{16}} \cr & = 2\frac{3}{{16}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to question \\ \sqrt{3 + \frac{33}{64}} \div \sqrt{9 + \frac{1}{7}} \times 2 \sqrt{3 \frac{1}{9}} \\ = \sqrt{\frac{225}{64}} \div \sqrt{\frac{64}{7}} \times 2 \sqrt{\frac{28}{9}} \\ = \sqrt{\frac{225}{64} \times \frac{7}{64} \times \frac{28}{9}} \times 2 \\ = \frac{5 \times 7}{8 \times 4} \times 2 \\ = \frac{35}{16} \\ = 2 \frac{3}{16} \end{aligned}

$\eqalign{ & {\text{According to question}} \cr & \sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}} \cr & = \sqrt {\frac{{225}}{{64}}} \div \sqrt {\frac{{64}}{7}} \times 2\sqrt {\frac{{28}}{9}} \cr & = \sqrt {\frac{{225}}{{64}} \times \frac{7}{{64}} \times \frac{{28}}{9}} \times 2 \cr & = \frac{{5 \times 7}}{{8 \times 4}} \times 2 \cr & = \frac{{35}}{{16}} \cr & = 2\frac{3}{{16}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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