x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{\text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} + \frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}{\text{ is = ?}}" /> x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{\text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} + \frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}{\text{ is = ?}}" /> x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{\text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} + \frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}{\text{ is = ?}}" />

The value of
x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?
  • 1-1
  • 20
  • 31
  • 4None of these
Answer:- 1
Explanation:-

Solution:
Given xepression ,(x+y−z)(x−y+z)(x+y+z)(x+z−y)+(y+x−z)(y−x+z)(x+y+z)(x+y−z)+(z+x−y)(z−x+y)(y+z+x)(y+z−x)=(x+y−z)(x+y+z)+(y−x+z)(x+y+z)+(x−y+z)(x+y+z)=(x+y−z)+(y−x+z)+(x−y+z)(x+y+z)=x+y+zx+y+z=1

Post your Comments

Your comments will be displayed only after manual approval.

", "text": "The value of
x2−(y−z)2(x+z)2−y2 + y2−(x−z)2(x+y)2−z2+z2−(x−y)2(y+z)2−x2 is = ?
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
Given xepression ,(x+y−z)(x−y+z)(x+y+z)(x+z−y)+(y+x−z)(y−x+z)(x+y+z)(x+y−z)+(z+x−y)(z−x+y)(y+z+x)(y+z−x)=(x+y−z)(x+y+z)+(y−x+z)(x+y+z)+(x−y+z)(x+y+z)=(x+y−z)+(y−x+z)+(x−y+z)(x+y+z)=x+y+zx+y+z=1
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Given xepression ,(x+y−z)(x−y+z)(x+y+z)(x+z−y)+(y+x−z)(y−x+z)(x+y+z)(x+y−z)+(z+x−y)(z−x+y)(y+z+x)(y+z−x)=(x+y−z)(x+y+z)+(y−x+z)(x+y+z)+(x−y+z)(x+y+z)=(x+y−z)+(y−x+z)+(x−y+z)(x+y+z)=x+y+zx+y+z=1
", "dateCreated": "7/24/2019 10:09:12 AM" } }
Test
Classes
E-Book