Let 0 < x < 1, then the correct inequality is = ?

Explanation:-

$$\eqalign{ & 0 < x < 1, \cr & {\text{Let }}x = \frac{4}{{10}} \cr & {\text{So}},\sqrt x = \frac{2}{{\sqrt {10} }}\,\& \, \cr & \,\,{x^2} = \frac{{16}}{{100}} = 0.16 \cr & {\text{Now}}, \cr & \because 0.16 < \frac{4}{{10}} < \frac{2}{{\sqrt {10} }} \cr & \therefore {x^2} < x < \sqrt x \cr}$$