14×627÷1089−−−−√=(?)3+14114×627÷1089=(?)3+14114 \times 627 \div \sqrt {1089} = {\left( ? \right)^3} + 141" /> 14×627÷1089−−−−√=(?)3+14114×627÷1089=(?)3+14114 \times 627 \div \sqrt {1089} = {\left( ? \right)^3} + 141" /> 14×627÷1089−−−−√=(?)3+14114×627÷1089=(?)3+14114 \times 627 \div \sqrt {1089} = {\left( ? \right)^3} + 141" />

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$14 \times 627 \div \sqrt{1089} = {(?)}^{3} + 141$ $14 \times 627 \div \sqrt {1089} = {\left( ? \right)^3} + 141$

15√5
2(125)²
325
44

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let the number be a \\ Given, \\ 14 \times 627 \div \sqrt{1089} \\ = {(a)}^{3} + 141 \\ \Rightarrow 14 \times 627 \div 33 \\ = a^{3} + 141 \\ \Rightarrow 266 = a^{3} + 141 \\ \Rightarrow a^{3} = 125 \\ \Rightarrow a = \sqrt[3]{125} \\ \Rightarrow a = 5 \end{aligned}

$\eqalign{ & {\text{Let the number be }}a{\text{ }} \cr & {\text{Given,}} \cr & 14 \times 627 \div \sqrt {1089} \cr & = {\left( a \right)^3} + 141 \cr & \Rightarrow 14 \times 627 \div 33 \cr & \,\,\,\,\,\,\, = {a^3} + 141 \cr & \Rightarrow 266 = {a^3} + 141 \cr & \Rightarrow {a^3} = 125 \cr & \Rightarrow a = \root 3 \of {125} \cr & \Rightarrow a = 5 \cr}$

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", "text": "

14 \times 627 \div \sqrt{1089} = {(?)}^{3} + 141

$14 \times 627 \div \sqrt {1089} = {\left( ? \right)^3} + 141$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution: