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Solve 14 × 627 ÷ √(1089) = (?)³ + 141

15√5
2(125)²
325
45

Answer:- 1

Explanation:-

Solution:

Let the missing number is a
Given,

\begin{aligned} 14 \times 627 \div \sqrt{(1089)} = {(a)}^{3} + 141 \\ \frac{14 \times 627}{\sqrt{1089}} = {(a)}^{3} + 141 \\ \frac{14 \times 627}{33} = a^{3} + 141 \\ 266 = a^{3} + 141 \\ a^{3} = 125 \\ a = \sqrt[3]{125} \\ a = 5 \end{aligned}

$\eqalign{ & 14 \times 627 \div \sqrt {\left( {1089} \right)} = {\left( a \right)^3} + 141 \cr & \frac{{14 \times 627}}{{\sqrt {1089} }} = {\left( a \right)^3} + 141 \cr & \frac{{14 \times 627}}{{33}} = {a^3} + 141 \cr & 266 = {a^3} + 141 \cr & {a^3} = 125 \cr & a = \root 3 \of {125} \cr & a = 5 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the missing number is a
Given,

\begin{aligned} 14 \times 627 \div \sqrt{(1089)} = {(a)}^{3} + 141 \\ \frac{14 \times 627}{\sqrt{1089}} = {(a)}^{3} + 141 \\ \frac{14 \times 627}{33} = a^{3} + 141 \\ 266 = a^{3} + 141 \\ a^{3} = 125 \\ a = \sqrt[3]{125} \\ a = 5 \end{aligned}

$\eqalign{ & 14 \times 627 \div \sqrt {\left( {1089} \right)} = {\left( a \right)^3} + 141 \cr & \frac{{14 \times 627}}{{\sqrt {1089} }} = {\left( a \right)^3} + 141 \cr & \frac{{14 \times 627}}{{33}} = {a^3} + 141 \cr & 266 = {a^3} + 141 \cr & {a^3} = 125 \cr & a = \root 3 \of {125} \cr & a = 5 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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