(0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?(0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}} = ?" /> (0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?(0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}} = ?" /> (0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?(0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}} = ?" />

(0.73)3+(0.27)3(0.73)2+(0.27)20.73×0.27=?

  • 10.27
  • 20.4087
  • 30.73
  • 41
Answer:- 1
Explanation:-

Solution:
Given,(0.73)3+(0.27)3(0.73)2+(0.27)20.73×0.27let a=0.73 and b=0.27=(0.73+0.27)[(0.73)2+(0.27)20.73×0.27](0.73)2+(0.27)20.73×0.27[a3+b3=(a+b)(a2+b2ab)]=0.73+0.27=1

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", "text": "
(0.73)3+(0.27)3(0.73)2+(0.27)20.73×0.27=?
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
Given,(0.73)3+(0.27)3(0.73)2+(0.27)20.73×0.27let a=0.73 and b=0.27=(0.73+0.27)[(0.73)2+(0.27)20.73×0.27](0.73)2+(0.27)20.73×0.27[a3+b3=(a+b)(a2+b2ab)]=0.73+0.27=1
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Given,(0.73)3+(0.27)3(0.73)2+(0.27)20.73×0.27let a=0.73 and b=0.27=(0.73+0.27)[(0.73)2+(0.27)20.73×0.27](0.73)2+(0.27)20.73×0.27[a3+b3=(a+b)(a2+b2ab)]=0.73+0.27=1
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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