(3–√−13–√)2simplifiesto:(3−13)2simplifiesto:{\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\,{\text{simplifies}}\,{\text{to:}}" /> (3–√−13–√)2simplifiesto:(3−13)2simplifiesto:{\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\,{\text{simplifies}}\,{\text{to:}}" /> (3–√−13–√)2simplifiesto:(3−13)2simplifiesto:{\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\,{\text{simplifies}}\,{\text{to:}}" />

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${(\sqrt{3} - \frac{1}{\sqrt{3}})}^{2} simplifies to:$ ${\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\,{\text{simplifies}}\,{\text{to:}}$

1 $\frac{3}{4}$ $\frac{3}{4}$
2 $\frac{4}{\sqrt{3}}$ $\frac{4}{{\sqrt 3 }}$
3 $\frac{4}{3}$ $\frac{4}{3}$
4None of these

Answer:- 1

Explanation:-

Solution:

\begin{aligned} {(\sqrt{3} - \frac{1}{\sqrt{3}})}^{2} \\ = {(\sqrt{3})}^{2} + {(\frac{1}{\sqrt{3}})}^{2} - 2 \times \sqrt{3} \times \frac{1}{\sqrt{3}} \\ = 3 + \frac{1}{3} - 2 \\ = 1 + \frac{1}{3} \\ = \frac{4}{3} \end{aligned}

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", "text": "

{(\sqrt{3} - \frac{1}{\sqrt{3}})}^{2} simplifies to:

${\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\,{\text{simplifies}}\,{\text{to:}}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} {(\sqrt{3} - \frac{1}{\sqrt{3}})}^{2} \\ = {(\sqrt{3})}^{2} + {(\frac{1}{\sqrt{3}})}^{2} - 2 \times \sqrt{3} \times \frac{1}{\sqrt{3}} \\ = 3 + \frac{1}{3} - 2 \\ = 1 + \frac{1}{3} \\ = \frac{4}{3} \end{aligned}

$\eqalign{ & {\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2} \cr & = {\left( {\sqrt 3 } \right)^2} + {\left( {\frac{1}{{\sqrt 3 }}} \right)^2} - 2 \times \sqrt 3 \times \frac{1}{{\sqrt 3 }} \cr & = 3 + \frac{1}{3} - 2 \cr & = 1 + \frac{1}{3} \cr & = \frac{4}{3} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: