Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is:\eqalign{
& {\text{If}}\,x = 3 + 2\sqrt 2 ,\,{\text{then}} \cr
& {\text{the}}\,{\text{value}}\,{\text{of}}\,\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)\,{\text{is:}} \cr} " />
Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is:\eqalign{
& {\text{If}}\,x = 3 + 2\sqrt 2 ,\,{\text{then}} \cr
& {\text{the}}\,{\text{value}}\,{\text{of}}\,\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)\,{\text{is:}} \cr} " />
Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is:\eqalign{
& {\text{If}}\,x = 3 + 2\sqrt 2 ,\,{\text{then}} \cr
& {\text{the}}\,{\text{value}}\,{\text{of}}\,\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)\,{\text{is:}} \cr} " />
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",
"text": "Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:
",
"dateCreated": "7/24/2019 10:09:12 AM",
"author": {
"@type": "Person",
"name": "Nitin Sir"
},
"answerCount": "4",
"acceptedAnswer": {
"@type": "Answer",
"text": "
Solution:
(x−−√−1x−−√)2=x+1x−2=(3+22–√)+1(3+22–√)−2=(3+22–√)+1(3+22–√)×(3−22–√)(3−22–√)−2=(3+22–√)+(3−22–√)−2=4∴(x−−√−1x−−√)=2
",
"dateCreated": "7/24/2019 10:09:12 AM",
"author": {
"@type": "Person",
"name": "Nitin Sir"
}
},
"suggestedAnswer": {
"@type": "Answer",
"text": "
Solution:
(x−−√−1x−−√)2=x+1x−2=(3+22–√)+1(3+22–√)−2=(3+22–√)+1(3+22–√)×(3−22–√)(3−22–√)−2=(3+22–√)+(3−22–√)−2=4∴(x−−√−1x−−√)=2
",
"dateCreated": "7/24/2019 10:09:12 AM"
}
}
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