Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is:\eqalign{ & {\text{If}}\,x = 3 + 2\sqrt 2 ,\,{\text{then}} \cr & {\text{the}}\,{\text{value}}\,{\text{of}}\,\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)\,{\text{is:}} \cr} " /> Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is:\eqalign{ & {\text{If}}\,x = 3 + 2\sqrt 2 ,\,{\text{then}} \cr & {\text{the}}\,{\text{value}}\,{\text{of}}\,\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)\,{\text{is:}} \cr} " /> Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is:\eqalign{ & {\text{If}}\,x = 3 + 2\sqrt 2 ,\,{\text{then}} \cr & {\text{the}}\,{\text{value}}\,{\text{of}}\,\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)\,{\text{is:}} \cr} " />

Ifx=3+22,thenthevalueof(x1x)is:

  • 11
  • 22
  • 32√2
  • 43√3
Answer:- 1
Explanation:-

Solution:
(x1x)2=x+1x2=(3+22)+1(3+22)2=(3+22)+1(3+22)×(322)(322)2=(3+22)+(322)2=4(x1x)=2

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", "text": "
Ifx=3+22,thenthevalueof(x1x)is:
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
(x1x)2=x+1x2=(3+22)+1(3+22)2=(3+22)+1(3+22)×(322)(322)2=(3+22)+(322)2=4(x1x)=2
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
(x1x)2=x+1x2=(3+22)+1(3+22)2=(3+22)+1(3+22)×(322)(322)2=(3+22)+(322)2=4(x1x)=2
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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