Simplify:⎛⎝32+3√−22−3√2−53–√⎞⎠=?Simplify:(32+3−22−32−53)=?\eqalign{ & {\text{Simplify:}} \cr & \left( {\frac{{\frac{3}{{2 + \sqrt 3 }} - \frac{2}{{2 - \sqrt 3 }}}}{{2 - 5\sqrt 3 }}} \right) = ? \cr} " /> Simplify:⎛⎝32+3√−22−3√2−53–√⎞⎠=?Simplify:(32+3−22−32−53)=?\eqalign{ & {\text{Simplify:}} \cr & \left( {\frac{{\frac{3}{{2 + \sqrt 3 }} - \frac{2}{{2 - \sqrt 3 }}}}{{2 - 5\sqrt 3 }}} \right) = ? \cr} " /> Simplify:⎛⎝32+3√−22−3√2−53–√⎞⎠=?Simplify:(32+3−22−32−53)=?\eqalign{ & {\text{Simplify:}} \cr & \left( {\frac{{\frac{3}{{2 + \sqrt 3 }} - \frac{2}{{2 - \sqrt 3 }}}}{{2 - 5\sqrt 3 }}} \right) = ? \cr} " />

Simplify:(32+3−22−32−53)=?
  • 11/2 - 5√3
  • 22 - 5√3
  • 31
  • 40
Answer:- 1
Explanation:-

Solution:
32+3−22−32−53=3(2−3)−2(2+3)(2+3)(2−3)2−53=6−33−4−23(2+3)(2−3)(2−53)=2−532−53=1

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", "text": "
Simplify:(32+3−22−32−53)=?
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
32+3−22−32−53=3(2−3)−2(2+3)(2+3)(2−3)2−53=6−33−4−23(2+3)(2−3)(2−53)=2−532−53=1
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
32+3−22−32−53=3(2−3)−2(2+3)(2+3)(2−3)2−53=6−33−4−23(2+3)(2−3)(2−53)=2−532−53=1
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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