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9³ × 6² ÷ 3³ = ?

1948
2972
3984
41012

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \frac{9^{3} \times 6^{2}}{3^{3}} \\ = \frac{{(3^{2})}^{3} \times {(3 \times 2)}^{2}}{3^{3}} \\ = \frac{3^{(3 \times 2)} \times 3^{2} \times 2^{2}}{3^{3}} \\ = \frac{3^{(6 + 2)} \times 2^{2}}{3^{3}} \\ = 3^{(8 - 3)} \times 2^{2} \\ = 3^{5} \times 2^{2} \\ = 243 \times 4 \\ = 972 \end{aligned}

$\eqalign{ & \frac{{{9^3} \times {6^2}}}{{{3^3}}} \cr & = \frac{{{{\left( {{3^2}} \right)}^3} \times {{\left( {3 \times 2} \right)}^2}}}{{{3^3}}} \cr & = \frac{{{3^{\left( {3 \times 2} \right)}} \times {3^2} \times {2^2}}}{{{3^3}}} \cr & = \frac{{{3^{\left( {6 + 2} \right)}} \times {2^2}}}{{{3^3}}} \cr & = {3^{\left( {8 - 3} \right)}} \times {2^2} \cr & = {3^5} \times {2^2} \cr & = 243 \times 4 \cr & = 972 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{9^{3} \times 6^{2}}{3^{3}} \\ = \frac{{(3^{2})}^{3} \times {(3 \times 2)}^{2}}{3^{3}} \\ = \frac{3^{(3 \times 2)} \times 3^{2} \times 2^{2}}{3^{3}} \\ = \frac{3^{(6 + 2)} \times 2^{2}}{3^{3}} \\ = 3^{(8 - 3)} \times 2^{2} \\ = 3^{5} \times 2^{2} \\ = 243 \times 4 \\ = 972 \end{aligned}

$\eqalign{ & \frac{{{9^3} \times {6^2}}}{{{3^3}}} \cr & = \frac{{{{\left( {{3^2}} \right)}^3} \times {{\left( {3 \times 2} \right)}^2}}}{{{3^3}}} \cr & = \frac{{{3^{\left( {3 \times 2} \right)}} \times {3^2} \times {2^2}}}{{{3^3}}} \cr & = \frac{{{3^{\left( {6 + 2} \right)}} \times {2^2}}}{{{3^3}}} \cr & = {3^{\left( {8 - 3} \right)}} \times {2^2} \cr & = {3^5} \times {2^2} \cr & = 243 \times 4 \cr & = 972 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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