The value of(3+22–√)−3+(3−22–√)−3=?The value of(3+22)−3+(3−22)−3=?\eqalign{ & {\text{The value of}} \cr & {\left( {3 + 2\sqrt 2 } \right)^{ - 3}} + {\left( {3 - 2\sqrt 2 } \right)^{ - 3}} = ? \cr} " /> The value of(3+22–√)−3+(3−22–√)−3=?The value of(3+22)−3+(3−22)−3=?\eqalign{ & {\text{The value of}} \cr & {\left( {3 + 2\sqrt 2 } \right)^{ - 3}} + {\left( {3 - 2\sqrt 2 } \right)^{ - 3}} = ? \cr} " /> The value of(3+22–√)−3+(3−22–√)−3=?The value of(3+22)−3+(3−22)−3=?\eqalign{ & {\text{The value of}} \cr & {\left( {3 + 2\sqrt 2 } \right)^{ - 3}} + {\left( {3 - 2\sqrt 2 } \right)^{ - 3}} = ? \cr} " />

The value of(3+22)−3+(3−22)−3=?
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  • 4198
Answer:- 1
Explanation:-

Solution:
(3+22)−3+(3−22)−3=(13+22)3+(13−22)3=(1(3−22)×3+223+22)3+(1(3+22)×3−223−22)3=(3−229−8)3+(3+229−8)3=(3−22)3+(3+22)3a=3−22b=3+22[∵a3+b3=(a+b)(a2+b2−ab)]=(3−22+3+22)(17+17−1)=(6)(33)=198

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", "text": "
The value of(3+22)−3+(3−22)−3=?
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
(3+22)−3+(3−22)−3=(13+22)3+(13−22)3=(1(3−22)×3+223+22)3+(1(3+22)×3−223−22)3=(3−229−8)3+(3+229−8)3=(3−22)3+(3+22)3a=3−22b=3+22[∵a3+b3=(a+b)(a2+b2−ab)]=(3−22+3+22)(17+17−1)=(6)(33)=198
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
(3+22)−3+(3−22)−3=(13+22)3+(13−22)3=(1(3−22)×3+223+22)3+(1(3+22)×3−223−22)3=(3−229−8)3+(3+229−8)3=(3−22)3+(3+22)3a=3−22b=3+22[∵a3+b3=(a+b)(a2+b2−ab)]=(3−22+3+22)(17+17−1)=(6)(33)=198
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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