[(0.73)3+(0.27)3(0.73)2+(0.27)2−(0.73)×(0.27)]simplifies to ?[(0.73)3+(0.27)3(0.73)2+(0.27)2−(0.73)×(0.27)]simplifies to ?\eqalign{ & \left[ {\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - \left( {0.73} \right) \times \left( {0.27} \right)}}} \right] \cr & {\text{simplifies to ?}} \cr} " /> [(0.73)3+(0.27)3(0.73)2+(0.27)2−(0.73)×(0.27)]simplifies to ?[(0.73)3+(0.27)3(0.73)2+(0.27)2−(0.73)×(0.27)]simplifies to ?\eqalign{ & \left[ {\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - \left( {0.73} \right) \times \left( {0.27} \right)}}} \right] \cr & {\text{simplifies to ?}} \cr} " /> [(0.73)3+(0.27)3(0.73)2+(0.27)2−(0.73)×(0.27)]simplifies to ?[(0.73)3+(0.27)3(0.73)2+(0.27)2−(0.73)×(0.27)]simplifies to ?\eqalign{ & \left[ {\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - \left( {0.73} \right) \times \left( {0.27} \right)}}} \right] \cr & {\text{simplifies to ?}} \cr} " />

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$\begin{aligned} [\frac{{(0.73)}^{3} + {(0.27)}^{3}}{{(0.73)}^{2} + {(0.27)}^{2} - (0.73) \times (0.27)}] \\ simplifies to ? \end{aligned}$ $\eqalign{ & \left[ {\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - \left( {0.73} \right) \times \left( {0.27} \right)}}} \right] \cr & {\text{simplifies to ?}} \cr}$

11
20.4087
30.73
40.27

Answer:- 1

Explanation:-

Solution:

\begin{aligned} let \\ a = 0.73 \\ b = 0.27 \\ = \frac{a^{3} + b^{3}}{a^{2} + b^{2} - a b} \\ = \frac{(a + b) (a^{2} + b^{2} - a b)}{(a^{2} + b^{2} - a b)} \\ = (a + b) \\ = (0.73 + 0.27) \\ = 1 \end{aligned}

$\eqalign{ & {\text{let}} \cr & a = 0.73 \cr & b = 0.27 \cr & = \frac{{{a^3} + {b^3}}}{{{a^2} + {b^2} - ab}} \cr & = \frac{{\left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)}}{{\left( {{a^2} + {b^2} - ab} \right)}} \cr & = \left( {a + b} \right) \cr & = \left( {0.73 + 0.27} \right) \cr & = 1 \cr}$

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", "text": "

\begin{aligned} [\frac{{(0.73)}^{3} + {(0.27)}^{3}}{{(0.73)}^{2} + {(0.27)}^{2} - (0.73) \times (0.27)}] \\ simplifies to ? \end{aligned}

$\eqalign{ & \left[ {\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - \left( {0.73} \right) \times \left( {0.27} \right)}}} \right] \cr & {\text{simplifies to ?}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} let \\ a = 0.73 \\ b = 0.27 \\ = \frac{a^{3} + b^{3}}{a^{2} + b^{2} - a b} \\ = \frac{(a + b) (a^{2} + b^{2} - a b)}{(a^{2} + b^{2} - a b)} \\ = (a + b) \\ = (0.73 + 0.27) \\ = 1 \end{aligned}

$\eqalign{ & {\text{let}} \cr & a = 0.73 \cr & b = 0.27 \cr & = \frac{{{a^3} + {b^3}}}{{{a^2} + {b^2} - ab}} \cr & = \frac{{\left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)}}{{\left( {{a^2} + {b^2} - ab} \right)}} \cr & = \left( {a + b} \right) \cr & = \left( {0.73 + 0.27} \right) \cr & = 1 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} let \\ a = 0.73 \\ b = 0.27 \\ = \frac{a^{3} + b^{3}}{a^{2} + b^{2} - a b} \\ = \frac{(a + b) (a^{2} + b^{2} - a b)}{(a^{2} + b^{2} - a b)} \\ = (a + b) \\ = (0.73 + 0.27) \\ = 1 \end{aligned}

$\eqalign{ & {\text{let}} \cr & a = 0.73 \cr & b = 0.27 \cr & = \frac{{{a^3} + {b^3}}}{{{a^2} + {b^2} - ab}} \cr & = \frac{{\left( {a + b} \right)\left( {{a^2} + {b^2} - ab} \right)}}{{\left( {{a^2} + {b^2} - ab} \right)}} \cr & = \left( {a + b} \right) \cr & = \left( {0.73 + 0.27} \right) \cr & = 1 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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