If 2x=32−−√3then x is equal to=?If 2x=323then x is equal to=?\eqalign{ & {\text{If }}{{\text{2}}^x} = \root 3 \of {32} \cr & {\text{then }}x{\text{ is equal to}} = ? \cr} " /> If 2x=32−−√3then x is equal to=?If 2x=323then x is equal to=?\eqalign{ & {\text{If }}{{\text{2}}^x} = \root 3 \of {32} \cr & {\text{then }}x{\text{ is equal to}} = ? \cr} " /> If 2x=32−−√3then x is equal to=?If 2x=323then x is equal to=?\eqalign{ & {\text{If }}{{\text{2}}^x} = \root 3 \of {32} \cr & {\text{then }}x{\text{ is equal to}} = ? \cr} " />

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$\begin{aligned} If 2^{x} = \sqrt[3]{32} \\ then x is equal to = ? \end{aligned}$ $\eqalign{ & {\text{If }}{{\text{2}}^x} = \root 3 \of {32} \cr & {\text{then }}x{\text{ is equal to}} = ? \cr}$

15
23
3³/₅
4⁵/₃

Answer:- 1

Explanation:-

Solution:

\begin{aligned} 2^{x} = \sqrt[3]{32} \\ \Rightarrow 2^{x} = {(32)}^{\frac{1}{3}} = {(2^{5})}^{\frac{1}{3}} \\ \Rightarrow x = \frac{5}{3} \end{aligned}

$\eqalign{ & {{\text{2}}^x} = \root 3 \of {32} \cr & \Rightarrow {{\text{2}}^x} = {\left( {32} \right)^{\frac{1}{3}}} = {\left( {{2^5}} \right)^{\frac{1}{3}}} \cr & \Rightarrow x = \frac{5}{3} \cr}$

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", "text": "

\begin{aligned} If 2^{x} = \sqrt[3]{32} \\ then x is equal to = ? \end{aligned}

$\eqalign{ & {\text{If }}{{\text{2}}^x} = \root 3 \of {32} \cr & {\text{then }}x{\text{ is equal to}} = ? \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 2^{x} = \sqrt[3]{32} \\ \Rightarrow 2^{x} = {(32)}^{\frac{1}{3}} = {(2^{5})}^{\frac{1}{3}} \\ \Rightarrow x = \frac{5}{3} \end{aligned}

$\eqalign{ & {{\text{2}}^x} = \root 3 \of {32} \cr & \Rightarrow {{\text{2}}^x} = {\left( {32} \right)^{\frac{1}{3}}} = {\left( {{2^5}} \right)^{\frac{1}{3}}} \cr & \Rightarrow x = \frac{5}{3} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: