82.4×23.7÷(16)1.3=2?82.4×23.7÷(16)1.3=2?{8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^?}" /> 82.4×23.7÷(16)1.3=2?82.4×23.7÷(16)1.3=2?{8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^?}" /> 82.4×23.7÷(16)1.3=2?82.4×23.7÷(16)1.3=2?{8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^?}" />

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$8^{2.4} \times 2^{3.7} \div {(16)}^{1.3} = 2^{?}$ ${8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^?}$

14.8
25.7
35.8
47.1

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let 8^{2.4} \times 2^{3.7} \div {(16)}^{1.3} = 2^{x} \\ Then, {(2^{3})}^{2.4} \times 2^{3.7} \div {(2^{4})}^{1.3} = 2^{x} \\ \Leftrightarrow 2^{(3 \times 2.4)} \times 2^{3.7} \div 2^{(4 \times 1.3)} = 2^{x} \\ \Leftrightarrow 2^{7.2} \times 2^{3.7} \div 2^{5.2} = 2^{x} \\ \Leftrightarrow 2^{x} = 2^{(7.2 + 3.7 - 5.2)} \\ \Leftrightarrow 2^{x} = 2^{5.7} \\ \Leftrightarrow x = 5.7 \end{aligned}

$\eqalign{ & {\text{Let }}{8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^x} \cr & {\text{Then,}}{\left( {{2^3}} \right)^{2.4}} \times {2^{3.7}} \div {\left( {{2^4}} \right)^{1.3}} = {2^x} \cr & \Leftrightarrow {2^{\left( {3 \times 2.4} \right)}} \times {2^{3.7}} \div {2^{\left( {4 \times 1.3} \right)}} = {2^x} \cr & \Leftrightarrow {2^{7.2}} \times {2^{3.7}} \div {2^{5.2}} = {2^x} \cr & \Leftrightarrow {2^x} = {2^{\left( {7.2 + 3.7 - 5.2} \right)}} \cr & \Leftrightarrow {2^x} = {2^{5.7}} \cr & \Leftrightarrow x = 5.7 \cr}$

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", "text": "

8^{2.4} \times 2^{3.7} \div {(16)}^{1.3} = 2^{?}

${8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^?}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let 8^{2.4} \times 2^{3.7} \div {(16)}^{1.3} = 2^{x} \\ Then, {(2^{3})}^{2.4} \times 2^{3.7} \div {(2^{4})}^{1.3} = 2^{x} \\ \Leftrightarrow 2^{(3 \times 2.4)} \times 2^{3.7} \div 2^{(4 \times 1.3)} = 2^{x} \\ \Leftrightarrow 2^{7.2} \times 2^{3.7} \div 2^{5.2} = 2^{x} \\ \Leftrightarrow 2^{x} = 2^{(7.2 + 3.7 - 5.2)} \\ \Leftrightarrow 2^{x} = 2^{5.7} \\ \Leftrightarrow x = 5.7 \end{aligned}

$\eqalign{ & {\text{Let }}{8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^x} \cr & {\text{Then,}}{\left( {{2^3}} \right)^{2.4}} \times {2^{3.7}} \div {\left( {{2^4}} \right)^{1.3}} = {2^x} \cr & \Leftrightarrow {2^{\left( {3 \times 2.4} \right)}} \times {2^{3.7}} \div {2^{\left( {4 \times 1.3} \right)}} = {2^x} \cr & \Leftrightarrow {2^{7.2}} \times {2^{3.7}} \div {2^{5.2}} = {2^x} \cr & \Leftrightarrow {2^x} = {2^{\left( {7.2 + 3.7 - 5.2} \right)}} \cr & \Leftrightarrow {2^x} = {2^{5.7}} \cr & \Leftrightarrow x = 5.7 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let 8^{2.4} \times 2^{3.7} \div {(16)}^{1.3} = 2^{x} \\ Then, {(2^{3})}^{2.4} \times 2^{3.7} \div {(2^{4})}^{1.3} = 2^{x} \\ \Leftrightarrow 2^{(3 \times 2.4)} \times 2^{3.7} \div 2^{(4 \times 1.3)} = 2^{x} \\ \Leftrightarrow 2^{7.2} \times 2^{3.7} \div 2^{5.2} = 2^{x} \\ \Leftrightarrow 2^{x} = 2^{(7.2 + 3.7 - 5.2)} \\ \Leftrightarrow 2^{x} = 2^{5.7} \\ \Leftrightarrow x = 5.7 \end{aligned}

$\eqalign{ & {\text{Let }}{8^{2.4}} \times {2^{3.7}} \div {\left( {16} \right)^{1.3}} = {2^x} \cr & {\text{Then,}}{\left( {{2^3}} \right)^{2.4}} \times {2^{3.7}} \div {\left( {{2^4}} \right)^{1.3}} = {2^x} \cr & \Leftrightarrow {2^{\left( {3 \times 2.4} \right)}} \times {2^{3.7}} \div {2^{\left( {4 \times 1.3} \right)}} = {2^x} \cr & \Leftrightarrow {2^{7.2}} \times {2^{3.7}} \div {2^{5.2}} = {2^x} \cr & \Leftrightarrow {2^x} = {2^{\left( {7.2 + 3.7 - 5.2} \right)}} \cr & \Leftrightarrow {2^x} = {2^{5.7}} \cr & \Leftrightarrow x = 5.7 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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