3x+1−−−−−√4=23x+14=2\root 4 \of {3x + 1} = 2" /> 3x+1−−−−−√4=23x+14=2\root 4 \of {3x + 1} = 2" /> 3x+1−−−−−√4=23x+14=2\root 4 \of {3x + 1} = 2" />

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Find the value of x in the expression : $\sqrt[4]{3 x + 1} = 2$ $\root 4 \of {3x + 1} = 2$

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \sqrt[4]{3 x + 1} = 2 \\ \Rightarrow {(\sqrt[4]{3 x + 1})}^{4} = 2^{4} \\ \Rightarrow {(3 x + 1)}^{4 \times \frac{1}{4}} = 16 \\ \Rightarrow 3 x = 15, \\ \Rightarrow x = 5 \end{aligned}

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", "text": "Find the value of x in the expression :

\sqrt[4]{3 x + 1} = 2

$\root 4 \of {3x + 1} = 2$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \sqrt[4]{3 x + 1} = 2 \\ \Rightarrow {(\sqrt[4]{3 x + 1})}^{4} = 2^{4} \\ \Rightarrow {(3 x + 1)}^{4 \times \frac{1}{4}} = 16 \\ \Rightarrow 3 x = 15, \\ \Rightarrow x = 5 \end{aligned}

$\eqalign{ & \root 4 \of {3x + 1} = 2 \cr & \Rightarrow {\left( {\root 4 \of {3x + 1} } \right)^4} = {2^4} \cr & \Rightarrow {\left( {3x + 1} \right)^{4 \times \frac{1}{4}}} = 16 \cr & \Rightarrow 3x = 15, \cr & \Rightarrow x = 5 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: