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An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?

1178
2195
3204
4488

Answer:- 1

Explanation:-

Solution:

Le the required time be x seconds.
More metres, More time (Direct Proportion)

\begin{aligned} ∴ 0.128 : 25 :: 1 : x \Leftrightarrow 0.128 x = 25 \times 1 \\ x = \frac{25}{0.128} = \frac{25 \times 1000}{128} \\ \Rightarrow x = 195.31 \end{aligned}

$\eqalign{ & \therefore 0.128:25::1:x\,\,\, \Leftrightarrow \,\,\,0.128x = 25 \times 1 \cr & x = \frac{{25}}{{0.128}} = \frac{{25 \times 1000}}{{128}} \cr & \Rightarrow x = 195.31 \cr}$
∴ Required time = 195 sec (approximately)

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∴ Required time = 195 sec (approximately) ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Le the required time be x seconds.
More metres, More time (Direct Proportion)

\begin{aligned} ∴ 0.128 : 25 :: 1 : x \Leftrightarrow 0.128 x = 25 \times 1 \\ x = \frac{25}{0.128} = \frac{25 \times 1000}{128} \\ \Rightarrow x = 195.31 \end{aligned}

$\eqalign{ & \therefore 0.128:25::1:x\,\,\, \Leftrightarrow \,\,\,0.128x = 25 \times 1 \cr & x = \frac{{25}}{{0.128}} = \frac{{25 \times 1000}}{{128}} \cr & \Rightarrow x = 195.31 \cr}$
∴ Required time = 195 sec (approximately) ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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