One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in-

Explanation:-

$$\eqalign{ & {\text{Let the slower pipe alone }} \cr & {\text{fill the tank in }}x{\text{ minutes}} \cr & {\text{Then,}} \cr & {\text{Faster pipe alone will fill it}} \cr & {\text{ in }}\frac{x}{3}{\text{ minutes}} \cr & \therefore \frac{1}{x} + \frac{3}{x} = \frac{1}{{36}} \cr & \Rightarrow \frac{4}{x} = \frac{1}{{36}} \cr & \Rightarrow x = 144 \cr & {\text{So slower pipe alone will fill}} \cr & {\text{ the tank in 144 min}}{\text{.}} \cr}$$