India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:

11.2 km
21.8 km
32.4 km
43.6 km

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Speed downstream \\ = (15 + 3) k m p h = 18 k m p h . \\ Distance travelled \\ = (18 \times \frac{12}{60}) k m = 3.6 k m \end{aligned}

$\eqalign{ & {\text{Speed}}\,{\text{downstream}} \cr & = \left( {15 + 3} \right)kmph = 18\,kmph. \cr & {\text{Distance}}\,{\text{travelled}} \cr & = \left( {18 \times \frac{{12}}{{60}}} \right)km = 3.6\,km \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Speed downstream \\ = (15 + 3) k m p h = 18 k m p h . \\ Distance travelled \\ = (18 \times \frac{12}{60}) k m = 3.6 k m \end{aligned}

$\eqalign{ & {\text{Speed}}\,{\text{downstream}} \cr & = \left( {15 + 3} \right)kmph = 18\,kmph. \cr & {\text{Distance}}\,{\text{travelled}} \cr & = \left( {18 \times \frac{{12}}{{60}}} \right)km = 3.6\,km \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book