Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:

116 hours
218 hours
320 hours
424 hours

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Speed upstream = 7.5 k m p h . \\ Speed downstream = 10.5 k m p h . \\ ∴ Total time taken \\ = (\frac{105}{7.5} + \frac{105}{10.5}) h o u r s \\ = 24 h o u r s \end{aligned}

$\eqalign{ & {\text{Speed}}\,{\text{upstream}} = 7.5\,kmph. \cr & {\text{Speed}}\,{\text{downstream}} = 10.5\,kmph. \cr & \therefore {\text{Total}}\,{\text{time}}\,{\text{taken}} \cr & = \left( {\frac{{105}}{{7.5}} + \frac{{105}}{{10.5}}} \right)hours \cr & = 24\,hours \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Speed upstream = 7.5 k m p h . \\ Speed downstream = 10.5 k m p h . \\ ∴ Total time taken \\ = (\frac{105}{7.5} + \frac{105}{10.5}) h o u r s \\ = 24 h o u r s \end{aligned}

$\eqalign{ & {\text{Speed}}\,{\text{upstream}} = 7.5\,kmph. \cr & {\text{Speed}}\,{\text{downstream}} = 10.5\,kmph. \cr & \therefore {\text{Total}}\,{\text{time}}\,{\text{taken}} \cr & = \left( {\frac{{105}}{{7.5}} + \frac{{105}}{{10.5}}} \right)hours \cr & = 24\,hours \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }