Iflog107=a,thenlog10(170)isequaltoIflog107=a,thenlog10(170)isequalto{\rm{If}}{\kern 1pt} \,{\kern 1pt} {\log _{10}}7 = a,{\kern 1pt} {\kern 1pt} {\rm{then}}\,{\kern 1pt} {\kern 1pt} {\log _{10}}\left( {{1 \over {70}}} \right){\rm{is}}\,{\kern 1pt} {\rm{equal}}\,{\kern 1pt} {\rm{to}}" /> Iflog107=a,thenlog10(170)isequaltoIflog107=a,thenlog10(170)isequalto{\rm{If}}{\kern 1pt} \,{\kern 1pt} {\log _{10}}7 = a,{\kern 1pt} {\kern 1pt} {\rm{then}}\,{\kern 1pt} {\kern 1pt} {\log _{10}}\left( {{1 \over {70}}} \right){\rm{is}}\,{\kern 1pt} {\rm{equal}}\,{\kern 1pt} {\rm{to}}" /> Iflog107=a,thenlog10(170)isequaltoIflog107=a,thenlog10(170)isequalto{\rm{If}}{\kern 1pt} \,{\kern 1pt} {\log _{10}}7 = a,{\kern 1pt} {\kern 1pt} {\rm{then}}\,{\kern 1pt} {\kern 1pt} {\log _{10}}\left( {{1 \over {70}}} \right){\rm{is}}\,{\kern 1pt} {\rm{equal}}\,{\kern 1pt} {\rm{to}}" />

India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

$I f \log_{10} 7 = a, t h e n \log_{10} (\frac{1}{70}) i s e q u a l t o$ ${\rm{If}}{\kern 1pt} \,{\kern 1pt} {\log _{10}}7 = a,{\kern 1pt} {\kern 1pt} {\rm{then}}\,{\kern 1pt} {\kern 1pt} {\log _{10}}\left( {{1 \over {70}}} \right){\rm{is}}\,{\kern 1pt} {\rm{equal}}\,{\kern 1pt} {\rm{to}}$

1- (1 + a)
2(1 + a)^-1
3^a/₁₀
4¹/_10a

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \log_{10} (\frac{1}{70}) \\ = \log_{10} 1 - \log_{10} 70 \\ = - \log_{10} (7 \times 10) \\ = - (\log_{10} 7 + \log_{10} 10) \\ = - (a + 1) \end{aligned}

Workspace Report

Post your Comments

", "text": "

I f \log_{10} 7 = a, t h e n \log_{10} (\frac{1}{70}) i s e q u a l t o

${\rm{If}}{\kern 1pt} \,{\kern 1pt} {\log _{10}}7 = a,{\kern 1pt} {\kern 1pt} {\rm{then}}\,{\kern 1pt} {\kern 1pt} {\log _{10}}\left( {{1 \over {70}}} \right){\rm{is}}\,{\kern 1pt} {\rm{equal}}\,{\kern 1pt} {\rm{to}}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \log_{10} (\frac{1}{70}) \\ = \log_{10} 1 - \log_{10} 70 \\ = - \log_{10} (7 \times 10) \\ = - (\log_{10} 7 + \log_{10} 10) \\ = - (a + 1) \end{aligned}

$\eqalign{ & {\log _{10}}\left( {{1 \over {70}}} \right) \cr & = {\log _{10}}1 - {\log _{10}}70 \cr & = - {\log _{10}}\left( {7 \times 10} \right) \cr & = - \left( {{{\log }_{10}}7 + {{\log }_{10}}10} \right) \cr & = - \left( {a + 1} \right) \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: