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If a^x = b^y, then:

1log ^a/_b = ^x/_y
2^{log a}/_{log b} = ^x/_y
3^{log a}/_{log b} = ^y/_x
4None of these

Answer:- 1

Explanation:-

Solution:

\begin{aligned} a^{x} = b^{y} \\ \Rightarrow \log a^{x} = \log b^{y} \\ \Rightarrow x \log a = y \log b \\ \Rightarrow \frac{\log a}{\log b} = \frac{y}{x} \end{aligned}

$\eqalign{ & {a^x} = {b^y} \cr & \Rightarrow \log {a^x} = \log {b^y} \cr & \Rightarrow x\log a = y\log b \cr & \Rightarrow {{\log a} \over {\log b}} = {y \over x} \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} a^{x} = b^{y} \\ \Rightarrow \log a^{x} = \log b^{y} \\ \Rightarrow x \log a = y \log b \\ \Rightarrow \frac{\log a}{\log b} = \frac{y}{x} \end{aligned}

$\eqalign{ & {a^x} = {b^y} \cr & \Rightarrow \log {a^x} = \log {b^y} \cr & \Rightarrow x\log a = y\log b \cr & \Rightarrow {{\log a} \over {\log b}} = {y \over x} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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