2log105+ log108 −12log104=?2log105+ log108 −12log104=?2{\log _{10}}^5 + {\text{ }}{\log _{10}}8{\text{ }} - \frac{1}{2}{\log _{10}}4 = ?" /> 2log105+ log108 −12log104=?2log105+ log108 −12log104=?2{\log _{10}}^5 + {\text{ }}{\log _{10}}8{\text{ }} - \frac{1}{2}{\log _{10}}4 = ?" /> 2log105+ log108 −12log104=?2log105+ log108 −12log104=?2{\log _{10}}^5 + {\text{ }}{\log _{10}}8{\text{ }} - \frac{1}{2}{\log _{10}}4 = ?" />

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$2 {\log_{10}}^{5} + \log_{10} 8 - \frac{1}{2} \log_{10} 4 = ?$ $2{\log _{10}}^5 + {\text{ }}{\log _{10}}8{\text{ }} - \frac{1}{2}{\log _{10}}4 = ?$

12
24
32 - 2log_{10_²}
44 - 4log_{10_²}

Answer:- 1

Explanation:-

Solution:

\begin{aligned} 2 \log_{10} 5 + \log_{10} 8 - \frac{1}{2} \log_{10} 4 \\ = \log 10 (5^{2}) + \log_{10} 8 - \log_{10} (4^{\frac{1}{2}}) \\ = \log_{10} 25 + \log_{10} 8 - \log_{10} 2 \\ = \log_{10} (\frac{25 \times 8}{2}) \\ = \log_{10} 100 \\ = 2 \end{aligned}

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", "text": "

2 {\log_{10}}^{5} + \log_{10} 8 - \frac{1}{2} \log_{10} 4 = ?

$2{\log _{10}}^5 + {\text{ }}{\log _{10}}8{\text{ }} - \frac{1}{2}{\log _{10}}4 = ?$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 2 \log_{10} 5 + \log_{10} 8 - \frac{1}{2} \log_{10} 4 \\ = \log 10 (5^{2}) + \log_{10} 8 - \log_{10} (4^{\frac{1}{2}}) \\ = \log_{10} 25 + \log_{10} 8 - \log_{10} 2 \\ = \log_{10} (\frac{25 \times 8}{2}) \\ = \log_{10} 100 \\ = 2 \end{aligned}

$\eqalign{ & 2{\log _{10}}5 + {\log _{10}}8 - \frac{1}{2}{\log _{10}}4 \cr & = \log 10\left( {{5^2}} \right) + {\log _{10}}8 - {\log _{10}}\left( {{4^{\frac{1}{2}}}} \right) \cr & = {\log _{10}}25 + {\log _{10}}8 - {\log _{10}}2 \cr & = {\log _{10}}\left( {\frac{{25 \times 8}}{2}} \right) \cr & = {\log _{10}}100 \cr & = 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: