Thevalueof(1log360+1log460+1log560)is−Thevalueof(1log360+1log460+1log560)is−\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}}\,\, \cr & \,\left( {\frac{1}{{{{\log }_3}60}} + \frac{1}{{{{\log }_4}60}} + \frac{1}{{{{\log }_5}60}}} \right)\,\,{\text{is}} - \cr} " /> Thevalueof(1log360+1log460+1log560)is−Thevalueof(1log360+1log460+1log560)is−\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}}\,\, \cr & \,\left( {\frac{1}{{{{\log }_3}60}} + \frac{1}{{{{\log }_4}60}} + \frac{1}{{{{\log }_5}60}}} \right)\,\,{\text{is}} - \cr} " /> Thevalueof(1log360+1log460+1log560)is−Thevalueof(1log360+1log460+1log560)is−\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}}\,\, \cr & \,\left( {\frac{1}{{{{\log }_3}60}} + \frac{1}{{{{\log }_4}60}} + \frac{1}{{{{\log }_5}60}}} \right)\,\,{\text{is}} - \cr} " />

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$\begin{aligned} The value of \\ (\frac{1}{\log_{3} 60} + \frac{1}{\log_{4} 60} + \frac{1}{\log_{5} 60}) is - \end{aligned}$ $\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}}\,\, \cr & \,\left( {\frac{1}{{{{\log }_3}60}} + \frac{1}{{{{\log }_4}60}} + \frac{1}{{{{\log }_5}60}}} \right)\,\,{\text{is}} - \cr}$

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Given expression \\ = \log_{60} 3 + \log_{60} 4 + \log_{60} 5 \\ = \log_{60} (3 \times 4 \times 5) \\ = \log_{60} 60 \\ = 1 \end{aligned}

$\eqalign{ & {\text{Given}}\,{\text{expression}} \cr & = {\log _{60}}3 + {\log _{60}}4 + {\log _{60}}5 \cr & = {\log _{60}}\left( {3 \times 4 \times 5} \right) \cr & = {\log _{60}}60 \cr & = 1 \cr}$

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", "text": "

\begin{aligned} The value of \\ (\frac{1}{\log_{3} 60} + \frac{1}{\log_{4} 60} + \frac{1}{\log_{5} 60}) is - \end{aligned}

$\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}}\,\, \cr & \,\left( {\frac{1}{{{{\log }_3}60}} + \frac{1}{{{{\log }_4}60}} + \frac{1}{{{{\log }_5}60}}} \right)\,\,{\text{is}} - \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Given expression \\ = \log_{60} 3 + \log_{60} 4 + \log_{60} 5 \\ = \log_{60} (3 \times 4 \times 5) \\ = \log_{60} 60 \\ = 1 \end{aligned}

$\eqalign{ & {\text{Given}}\,{\text{expression}} \cr & = {\log _{60}}3 + {\log _{60}}4 + {\log _{60}}5 \cr & = {\log _{60}}\left( {3 \times 4 \times 5} \right) \cr & = {\log _{60}}60 \cr & = 1 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: