Iflog107=a,thenlog10(170)isequalto−Iflog107=a,thenlog10(170)isequalto−\eqalign{ & {\text{If}}\,\,{\log _{10}}7 = a,{\text{then}}\,\,{\log _{10}}\left( {\frac{1}{{70}}} \right)\,\, \cr & {\text{is}}\,\,{\text{equal}}\,\,{\text{to}} - \cr} " /> Iflog107=a,thenlog10(170)isequalto−Iflog107=a,thenlog10(170)isequalto−\eqalign{ & {\text{If}}\,\,{\log _{10}}7 = a,{\text{then}}\,\,{\log _{10}}\left( {\frac{1}{{70}}} \right)\,\, \cr & {\text{is}}\,\,{\text{equal}}\,\,{\text{to}} - \cr} " /> Iflog107=a,thenlog10(170)isequalto−Iflog107=a,thenlog10(170)isequalto−\eqalign{ & {\text{If}}\,\,{\log _{10}}7 = a,{\text{then}}\,\,{\log _{10}}\left( {\frac{1}{{70}}} \right)\,\, \cr & {\text{is}}\,\,{\text{equal}}\,\,{\text{to}} - \cr} " />

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$\begin{aligned} If \log_{10} 7 = a, then \log_{10} (\frac{1}{70}) \\ is equal to - \end{aligned}$ $\eqalign{ & {\text{If}}\,\,{\log _{10}}7 = a,{\text{then}}\,\,{\log _{10}}\left( {\frac{1}{{70}}} \right)\,\, \cr & {\text{is}}\,\,{\text{equal}}\,\,{\text{to}} - \cr}$

1-(1 + a)
2(1 + a)^-1
3^a/₁₀
4¹/_10a

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \log_{10} (\frac{1}{70}) \\ = \log_{10} 1 - \log_{10} 70 \\ = - \log_{10} (7 \times 10) \\ = - (\log_{10} 7 + \log_{10} 10) \\ = - (a + 1) \end{aligned}

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", "text": "

\begin{aligned} If \log_{10} 7 = a, then \log_{10} (\frac{1}{70}) \\ is equal to - \end{aligned}

$\eqalign{ & {\text{If}}\,\,{\log _{10}}7 = a,{\text{then}}\,\,{\log _{10}}\left( {\frac{1}{{70}}} \right)\,\, \cr & {\text{is}}\,\,{\text{equal}}\,\,{\text{to}} - \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \log_{10} (\frac{1}{70}) \\ = \log_{10} 1 - \log_{10} 70 \\ = - \log_{10} (7 \times 10) \\ = - (\log_{10} 7 + \log_{10} 10) \\ = - (a + 1) \end{aligned}

$\eqalign{ & {\log _{10}}\left( {\frac{1}{{70}}} \right) \cr & = {\log _{10}}1 - {\log _{10}}70 \cr & = - {\log _{10}}\left( {7 \times 10} \right) \cr & = - \left( {{{\log }_{10}}7 + {{\log }_{10}}10} \right) \cr & = - \left( {a + 1} \right) \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: