Two dice are tossed. The probability that the total score is a prime number is:

1¹/₆
2⁵/₁₂
3¹/₂
4⁷/₉

Answer:- 1

Explanation:-

Solution:

Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.Then
E = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) }

\begin{aligned} ∴ n (E) = 15. \\ ∴ P (E) = \frac{n (E)}{n (S)} \\ = \frac{15}{36} \\ = \frac{5}{12} \end{aligned}

$\eqalign{ & \therefore n\left( E \right) = 15. \cr & \therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} \cr & = \frac{{15}}{{36}} \cr & = \frac{5}{{12}} \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} ∴ n (E) = 15. \\ ∴ P (E) = \frac{n (E)}{n (S)} \\ = \frac{15}{36} \\ = \frac{5}{12} \end{aligned}

$\eqalign{ & \therefore n\left( E \right) = 15. \cr & \therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} \cr & = \frac{{15}}{{36}} \cr & = \frac{5}{{12}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }