The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum is:

1Rs. 1800
2Rs. 1450
3Rs. 1360
4Rs. 6800

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Sum = \frac{S . I . \times T . D .}{(S . I .) - (T . D .)} \\ = \frac{85 \times 80}{(85 - 80)} \\ = R s . 1360. \end{aligned}

$\eqalign{ & {\text{Sum}} = \frac{{S.I. \times T.D.}}{{\left( {S.I.} \right) - \left( {T.D.} \right)}} \cr & = \frac{{85 \times 80}}{{\left( {85 - 80} \right)}} \cr & = Rs.\,1360. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Sum = \frac{S . I . \times T . D .}{(S . I .) - (T . D .)} \\ = \frac{85 \times 80}{(85 - 80)} \\ = R s . 1360. \end{aligned}

$\eqalign{ & {\text{Sum}} = \frac{{S.I. \times T.D.}}{{\left( {S.I.} \right) - \left( {T.D.} \right)}} \cr & = \frac{{85 \times 80}}{{\left( {85 - 80} \right)}} \cr & = Rs.\,1360. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }