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If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is:

1Rs. 768
2Rs. 968
3Rs. 1960
4Rs. 2400

Answer:- 1

Explanation:-

Solution:

\begin{aligned} P . W . = \frac{100 \times T . D .}{R \times T} \\ = \frac{100 \times 168}{14 \times 2} \\ = 600. \\ ∴ Sum = (P . W . + T . D .) \\ = R s . (600 + 168) \\ = R s . 768 \end{aligned}

$\eqalign{ & P.W. = \frac{{100 \times T.D.}}{{R \times T}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{100 \times 168}}{{14 \times 2}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 600. \cr & \therefore {\text{Sum}} = \left( {P.W. + T.D.} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\left( {600 + 168} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,768 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} P . W . = \frac{100 \times T . D .}{R \times T} \\ = \frac{100 \times 168}{14 \times 2} \\ = 600. \\ ∴ Sum = (P . W . + T . D .) \\ = R s . (600 + 168) \\ = R s . 768 \end{aligned}

$\eqalign{ & P.W. = \frac{{100 \times T.D.}}{{R \times T}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{100 \times 168}}{{14 \times 2}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 600. \cr & \therefore {\text{Sum}} = \left( {P.W. + T.D.} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\left( {600 + 168} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,768 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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