Choose the missing terms out of the given alternatives : J2Z, K4X, I7V, ? , H16R, M22P
  • 1I11T
  • 2L11S
  • 3L12T
  • 4L11T
Answer:- 1
Explanation:-

Solution:
The first letters in odd numbered terms from series. J - 1 I - 1 H and in even numbered terms from series K + 1 L + 1 M
Middle Number : 2 + 2 4 + 3 7 + 4 11 + 5 16 + 6 22
3rd letter : Z - 2 X - 2 V - 2 T - 2 R - - 2 P

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