Sin 𝛉 = 𝟐𝒂𝒃/(𝒂𝟐+𝒃𝟐 ), तो tan 𝜽 का मान है-

  • 1

    (𝒂𝟐−𝒃𝟐)/𝟐𝒂𝒃

  • 2

     𝟐𝒂𝒃/𝒂𝟐−𝒃𝟐

  • 3

    (𝒂𝟐−𝒃𝟐)/(𝒂𝟐+𝒃𝟐)

  • 4

    (𝒂𝟐+𝒃𝟐)/(𝒂𝟐−𝒃𝟐)

Answer:- 2

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