यदि sinθ =  a/√a2 + b2, 0° < θ < 90° तो secθ + tanθ का मान है -

  • 1

    √a2 + b2 + b/a

  • 2

    √a2 + b2 + a/2b

  • 3

    √a2 + b2 + b/2a

  • 4

    √a2 + b2 + a/b

Answer:- 4

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