2 cos (π›‰βˆ’π…/𝟐)+3 sin (𝛉+𝝅/𝟐)- (3 sin𝛉 + 2 cos 𝛉) = ?

  • 1

    Cos𝛉 – sin𝛉

  • 2

    Sin𝛉 – cos𝛉

  • 3

    Sin𝛉 + cos𝛉

  • 4

    Cot𝛉 – tan𝛉

Answer:- 1

Post your Comments

Your comments will be displayed only after manual approval.

Test
Classes
E-Book