From I, We know that in a class of 25 students, Amit ranks 18th from the bottom and 8th from the top.
Sachin is three ranks above Amit and so, Sachin ranks 5th from the top.
From II, Deepti ranks 23rd from the bottom and hence, 3rd from the top. Sachin, being 2 ranks below Deepti, is, thus, 5th from the top.
From the two statements given in I, the code for the only common word 'beautiful' can be determined.
From the two statements given in II, the code for the only common word 'red' can be determined.
In I and II, the common words are 'rose and 'flower' and the common code words are 'de' and 'la'. So, the code for 'flower' is either 'de' or 'la'.
From I, we have: B > T, B > C, V > B. Thus, V is heavier than each one of B, T and C. But V is not the heaviest. So, E is the heaviest.
Thus, we have the order. E>V>B>T>C or E>V>B>C>T. Clearly, B is third from the top.
From I, we conclude that the man is the only son of Tanya's grandfather i.e. he is Tanya's father or Tanya is the man's daughter.
From II, we conclude that the man's father is Tanya's grandfather. Since the man has no brothers or sisters, so he is Tanya's father or Tanya is the man's daughter.
From I, total number of doctors in town = (1/700 x N) , where N = total number of residents in town. But, the value of N is not known.
From II, total number of doctors in town
= (Number of wards in town) x (Number of doctors in each ward)
= 16 x 16 = 256.
Since 8th to the left of 12th from the right is 20th from the right, so from I, we know that Vishakha is 5th from left and 20th from right i.e. there are 4 children to the left and 19 to the right of Vishakha. So, there are (4 + 1 + 19) i.e. 24 children in the row.
From II, Nisha is 7th from right and 18th from left end of the row.
So, there are (6 + 1 + 17) = 24 children in the row.