Unit digit in 34 = 1 ⇒ Unit digit in (34)16 = 1
Therefore Unit digit in 365 = Unit digit in [ (34)16 x 3 ] = (1 x 3) = 3
Unit digit in 659 = 6
Unit digit in 74 ⇒ Unit digit in (74)17 is 1.
Unit digit in 771 = Unit digit in [(74)17 x 73] = (1 x 3) = 3
Therefore Required digit = Unit digit in (3 x 6 x 3) = 4.
Let Sn = (2 + 4 + 6 + ..... + 30). This is an A.P. in which a = 2, d = 2 and l = 30
Let the number of terms be n Then,
a + (n - 1)d = 30
⇒ 2 + (n - 1) x 2 = 30
⇒ n = 15
437 > 22
All prime numbers less than 22 are : 2, 3, 5, 7, 11, 13, 17, 19.
161 is divisible by 7, and 221 is divisible by 13.
373 is not divisible by any of the above prime numbers.
Therefore373 is prime.
Let the given number be 476 xy 0
Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3
And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11
x - y - 3 = 0 ⇒ y = x - 3
(17 + x + y) = (17 + x + x - 3) = (2x + 14)
⇒ x = 2 or x = 8
⇒ x = 8 and y = 5
24 = 3 x 8, where 3 and 8 co-prime
Clearly, 35718 is not divisible by 8, as 718 is not divisible by 8
Similarly, 63810 is not divisible by 8 and 537804 is not divisible by 8
Consider option (D),
Sum of digits = (3 + 1 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 3
Also, 736 is divisible by 8
∴ 3125736 is divisible by (3 x 8), i.e., 24