Let the first part = Rs. x∴Hence second part = Rs. (12000−x)According to the qoestion,⇒x×12×3100=(12000−x)×9×162×100⇒36x=72(12000−x)⇒x=24000−2x⇒3x=24000⇒x=Rs. 80001st part = Rs. 80002nd part = Rs. (12000−8000)=Rs. 4000 Hence maximum part = Rs. 8000
Note : In such type of questions to save your valuable time follow the given below method.
Let two parts P1 and P2 respectively
⇒P1×36100×1=P2×92×16100×1⇒P1×4=8P2⇒P1P2=21⇒P1:P2=2:1Hence greater part = 12000(2+1)×2=Rs. 8000
Where x is the no. of times the sum becomes of itself. Here the sum is getting 3 times.
Therefore, x = 3
Where t is the time taken by sum to become x times of itself. Here, t = 12 years
By the short trick approach, we get
Alternative Method :
Let the principal be P and in the 2nd scenario, SI = 2P