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Percentage - 01
01.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
1
4.37%
2
5%
3
6%
4
8.75%
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Answer:-
1
Explanation:-
Solution:
Increase
in
10
years
=
(
262500
−
175000
)
=
87500.
Increase
%
=
(
87500
175000
×
100
)
%
=
50
%
.
∴
Required
average
=
(
50
10
)
%
=
5
%
.
Increase
in
10
years
=
(
262500
−
175000
)
=
87500.
Increase
%
=
(
87500
175000
×
100
)
%
=
50
%
.
∴
Required
average
=
(
50
10
)
%
=
5
%
.
02.
Rajeev buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods.
1
Rs. 6876.10
2
Rs. 6999.20
3
Rs. 6654
4
Rs. 7000
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Answer:-
1
Explanation:-
Solution:
Rebate
=
6
%
of
R
s
.
6650
=
R
s
.
(
6
100
×
6650
)
=
R
s
.
399.
Sales
tax
=
10
%
of
R
s
.
(
6650
−
399
)
=
R
s
.
(
10
100
×
6251
)
=
R
s
.
625.10
∴
Final
amount
=
R
s
.
(
6251
+
625.10
)
=
R
s
.
6876.10
Rebate
=
6
%
of
R
s
.
6650
=
R
s
.
(
6
100
×
6650
)
=
R
s
.
399.
Sales
tax
=
10
%
of
R
s
.
(
6650
−
399
)
=
R
s
.
(
10
100
×
6251
)
=
R
s
.
625.10
∴
Final
amount
=
R
s
.
(
6251
+
625.10
)
=
R
s
.
6876.10
03.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
1
Rs. 200
2
Rs. 250
3
Rs. 300
4
None of these
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Answer:-
1
Explanation:-
Solution:
Let
the
sum
paid
to
y
per
week
be
R
s
.
z
.
Then
,
z
+
120
%
o
f
z
=
550.
⇒
z
+
120
100
z
=
550
⇒
11
5
z
=
550
⇒
z
=
(
550
×
5
11
)
=
250.
Let
the
sum
paid
to
y
per
week
be
R
s
.
z
.
Then
,
z
+
120
%
o
f
z
=
550.
⇒
z
+
120
100
z
=
550
⇒
11
5
z
=
550
⇒
z
=
(
550
×
5
11
)
=
250.
04.
Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
1
57%
2
60%
3
65%
4
90%
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Answer:-
4
Explanation:-
Solution:
Total number of votes polled = (1136 + 7636 + 11628) = 20400.
∴ Required percentage =
(
11628
20400
×
100
)
%
=
57
%
.
(
11628
20400
×
100
)
%
=
57
%
.
05.
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
1
2700
2
2900
3
3000
4
3100
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Answer:-
1
Explanation:-
Solution:
Number of valid votes = 80% of 7500 = 6000.
∴ Valid votes polled by other candidate = 45% of 6000
=
(
45
100
×
6000
)
=
2700.
06.
A student multiplied a number by
3
/
5
instead of
3
/
5
.
What is the percentage error in the calculation?
1
34%
2
44%
3
54%
4
64%
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Answer:-
4
Explanation:-
Solution:
Let
the
number
be
x
.
Then,
error
=
5
3
x
−
3
5
x
=
16
15
x
.
Error
%
=
(
16
x
15
×
3
5
x
×
100
)
%
=
64
%
.
Let
the
number
be
x
.
Then,
error
=
5
3
x
−
3
5
x
=
16
15
x
.
Error
%
=
(
16
x
15
×
3
5
x
×
100
)
%
=
64
%
.
07.
In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 48. What is the total number of students in the school?
1
72
2
80
3
120
4
150
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Answer:-
4
Explanation:-
Solution:
Let the number of students be
x
. Then,
Number of students above 8 years of age
=
(
100
−
20
)
%
of
x
=
80
%
of
x
.
∴
80
%
of
x
=
48
+
2
3
of
48
⇒
80
100
x
=
80
⇒
x
=
100.
=
(
100
−
20
)
%
of
x
=
80
%
of
x
.
∴
80
%
of
x
=
48
+
2
3
of
48
⇒
80
100
x
=
80
⇒
x
=
100.
08.
If 20% of
a
=
b
, then
b
% of 20 is the same as:
1
4% of
a
2
5% of
a
3
20% of
a
4
None of these
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Answer:-
4
Explanation:-
Solution:
20
%
of
a
=
b
⇒
20
100
a
=
b
.
∴
b
%
of
20
=
(
b
100
×
20
)
=
(
20
100
a
×
1
100
×
20
)
=
4
100
a
=
4
%
of
a
.
20
%
of
a
=
b
⇒
20
100
a
=
b
.
∴
b
%
of
20
=
(
b
100
×
20
)
=
(
20
100
a
×
1
100
×
20
)
=
4
100
a
=
4
%
of
a
.
09.
If A =
x
% of
y
and B =
y
% of
x
, then which of the following is true?
1
A is smaller than B.
2
A is greater than B
3
Relationship between A and B cannot be determined.
4
If
x
is smaller than
y
, then A is greater than B.
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Answer:-
4
Explanation:-
Solution:
x
%
of
y
=
(
x
100
×
y
)
=
(
y
100
×
x
)
=
y
%
of
x
∴
A
=
B
10.
What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
1
1
2
14
3
20
4
21
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Answer:-
1
Explanation:-
Solution:
Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
=
(
14
70
×
100
)
%
=
20
%
.
=
(
14
70
×
100
)
%
=
20
%
.
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