According to the question,
As they complete the same work in same time
6 men + 5 women
= 6 men + 3 men
= 9 men
If, 3 men does a work in 12 days
1 men does a work in 12 × 3
9 men does a work in
12×39
= 4 days
Alternate :
3 men×12=5 women×12menwomen=53Total work=3×5×12=15×12=180 unitsEfficiency of 6 men+5 women=6×5+5×3=45Time taken by 6 men+5 women=18045=4 days
According to the question,15 men=20 days300 men=1 days.....(i)24 women=20 days480 men=1 days......(ii)Compare equation (i) and (ii)300 men=480 women5 men=8 women.....(iii)10 men+8 women=?10 men+5 men=?15men=?
15 men×20 days
=
15 men
×
x days
Alternate
15m×20 days=24w×20 daysmw=85
So, 1 man work 8 units work in one day
and 1 woman work 5 units work in one day
Total work = 15 × 8 × 20
Hence, (10 men + 8 women) work whole in D days
(10m+8w)×D=15×8×20(10×8+8×5)×D=15×8×20(10+40)×D=15×8×20D=20 days
2(A + B + C)'s1day'swork=(130+124+120)=15120=18∴(A + B + C)'s1day'swork=12×8=116WorkdonebyA,B,Cin10days=1016=58Remainingwork=(1−58)=38A's1day'swork=(116−124)=148Now,148workisdonebyAin1daySo,38workwillbedonebyAin(48×38)=18days
(A + B)'s1day'swork=(115+110)=16WorkdonebyAandBin2days=(16×2)=13Remainingwork=(1−13)=23Now,115workisdonebyAin1day∴23workwillbedonebyain(15×23)=10daysHence,thetotaltimetaken=(10+2)=12days