Let the initial fares of 1st, 2nd and 3rd class be Rs. 8x, Rs. 6x, and Rs. 3x respectively.
Revised fare of 1st class = 56of Rs.8x=Rs.(20x3).Revised fare of 2nd class = 1112of Rs.6x=Rs.(11x2).$$\begin{array}{rl}& \text{Revised fare of 1st class}\\ & \text{=}\frac{5}{6}\text{of Rs}.8x\\ & =\text{Rs}.\left(\frac{20x}{3}\right).\\ & \text{Revised fare of}2\text{nd class}\\ & \text{=}\frac{11}{12}\text{of Rs}.6x\\ & =\text{Rs}\text{.}\left(\frac{11x}{2}\right).\end{array}$$
Let the number of passengers of 1st, 2nd and 3rd class be 9y, 12y and 26y respectively.
Then,
Let the number of coins with Lalita, Palita and Salita in the end be 24x, 21x and 16x respectively.
Then,
Number of coins received by Lalita, Palita and Salita from their mother are
(24x + 50), (21x + 85) and (16x + 39) respectively.
So, (24x + 50) + (21x + 85) + (16x + 39) = 3224
⇒ 61x = 3050
⇒ x = 50.
Hence, number of coins received by Lalita from her mother
= (24 × 50 + 50)
= 1250.